Solve =600-40=50^circmm

$$= 600 - 40 = 50 ^ { \circ } mm$$

Solve for m

$$m = \frac{2 \sqrt{70}}{5} \approx 3.346640106$$

$$m = -\frac{2 \sqrt{70}}{5} \approx -3.346640106$$

Steps by Finding Square Root

Multiply m and m to get m^{2}.

$$600-40=50m^{2}$$

Subtract 40 from 600 to get 560.

$$560=50m^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$50m^{2}=560$$

Divide both sides by 50.

$$m^{2}=\frac{560}{50}$$

Reduce the fraction \frac{560}{50} to lowest terms by extracting and canceling out 10.

$$m^{2}=\frac{56}{5}$$

Take the square root of both sides of the equation.

$$m=\frac{2\sqrt{70}}{5} m=-\frac{2\sqrt{70}}{5}$$

Steps Using the Quadratic Formula

Multiply m and m to get m^{2}.

$$600-40=50m^{2}$$

Subtract 40 from 600 to get 560.

$$560=50m^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$50m^{2}=560$$

Subtract 560 from both sides.

$$50m^{2}-560=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 50 for a, 0 for b, and -560 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\times 50\left(-560\right)}}{2\times 50}$$

Square 0.

$$m=\frac{0±\sqrt{-4\times 50\left(-560\right)}}{2\times 50}$$

Multiply -4 times 50.

$$m=\frac{0±\sqrt{-200\left(-560\right)}}{2\times 50}$$

Multiply -200 times -560.

$$m=\frac{0±\sqrt{112000}}{2\times 50}$$

Take the square root of 112000.

$$m=\frac{0±40\sqrt{70}}{2\times 50}$$

Multiply 2 times 50.

$$m=\frac{0±40\sqrt{70}}{100}$$

Now solve the equation m=\frac{0±40\sqrt{70}}{100} when ± is plus.

$$m=\frac{2\sqrt{70}}{5}$$

Now solve the equation m=\frac{0±40\sqrt{70}}{100} when ± is minus.

$$m=-\frac{2\sqrt{70}}{5}$$

The equation is now solved.

$$m=\frac{2\sqrt{70}}{5} m=-\frac{2\sqrt{70}}{5}$$