Solve =40+180/41=40+4*38=44*38

$$= 40 + \frac { 180 } { 41 } = 40 + 4 \cdot 38 = 44 \cdot 38$$

Verify

Solution Steps

Convert 40 to fraction \frac{1640}{41}.

$$\frac{1640}{41}+\frac{180}{41}=40+4\times 38\text{ and }40+4\times 38=44\times 38$$

Since \frac{1640}{41} and \frac{180}{41} have the same denominator, add them by adding their numerators.

$$\frac{1640+180}{41}=40+4\times 38\text{ and }40+4\times 38=44\times 38$$

Add 1640 and 180 to get 1820.

$$\frac{1820}{41}=40+4\times 38\text{ and }40+4\times 38=44\times 38$$

Multiply 4 and 38 to get 152.

$$\frac{1820}{41}=40+152\text{ and }40+4\times 38=44\times 38$$

Add 40 and 152 to get 192.

$$\frac{1820}{41}=192\text{ and }40+4\times 38=44\times 38$$

Convert 192 to fraction \frac{7872}{41}.

$$\frac{1820}{41}=\frac{7872}{41}\text{ and }40+4\times 38=44\times 38$$

Compare \frac{1820}{41} and \frac{7872}{41}.

$$\text{false}\text{ and }40+4\times 38=44\times 38$$

Multiply 4 and 38 to get 152.

$$\text{false}\text{ and }40+152=44\times 38$$

Add 40 and 152 to get 192.

$$\text{false}\text{ and }192=44\times 38$$

Multiply 44 and 38 to get 1672.

$$\text{false}\text{ and }192=1672$$

Compare 192 and 1672.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$