Solve =3*(-1)^2-2*(-1)*(-4)-(-4)^2

$$= 3 \cdot ( - 1 ) ^ { 2 } - 2 \cdot ( - 1 ) \cdot ( - 4 ) - ( - 4 ) ^ { 2 }$$

Evaluate

$$-21$$

Solution Steps

Calculate -1 to the power of 2 and get 1.

$$3\times 1-2\left(-1\right)\left(-4\right)-\left(-4\right)^{2}$$

Multiply 3 and 1 to get 3.

$$3-2\left(-1\right)\left(-4\right)-\left(-4\right)^{2}$$

Multiply 2 and -1 to get -2.

$$3-\left(-2\left(-4\right)\right)-\left(-4\right)^{2}$$

Multiply -2 and -4 to get 8.

$$3-8-\left(-4\right)^{2}$$

Subtract 8 from 3 to get -5.

$$-5-\left(-4\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$-5-16$$

Subtract 16 from -5 to get -21.

$$-21$$

Factor

$$-21$$