Solve =22^3-(-3)^3-3frac{1}2^-2

$$= 22 ^ { 3 } - ( - 3 ) ^ { 3 } - 3 \frac { 1 } { 2 } ^ { - 2 }$$

Evaluate

$$\frac{523071}{49}\approx 10674.918367347$$

Solution Steps

Calculate 22 to the power of 3 and get 10648.

$$10648-\left(-3\right)^{3}-\left(\frac{3\times 2+1}{2}\right)^{-2}$$

Calculate -3 to the power of 3 and get -27.

$$10648-\left(-27\right)-\left(\frac{3\times 2+1}{2}\right)^{-2}$$

The opposite of -27 is 27.

$$10648+27-\left(\frac{3\times 2+1}{2}\right)^{-2}$$

Add 10648 and 27 to get 10675.

$$10675-\left(\frac{3\times 2+1}{2}\right)^{-2}$$

Multiply 3 and 2 to get 6.

$$10675-\left(\frac{6+1}{2}\right)^{-2}$$

Add 6 and 1 to get 7.

$$10675-\left(\frac{7}{2}\right)^{-2}$$

Calculate \frac{7}{2} to the power of -2 and get \frac{4}{49}.

$$10675-\frac{4}{49}$$

Subtract \frac{4}{49} from 10675 to get \frac{523071}{49}.

$$\frac{523071}{49}$$

Factor

$$\frac{3 ^ {3} \cdot 19373}{7 ^ {2}} = 10674\frac{45}{49} = 10674.918367346938$$