Solve =2(-1/2)^3-3(-1/2)^2+4(-1/2)+3

$$= 2 ( - \frac { 1 } { 2 } ) ^ { 3 } - 3 ( - \frac { 1 } { 2 } ) ^ { 2 } + 4 ( - \frac { 1 } { 2 } ) + 3$$

Evaluate

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Solution Steps

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$2\left(-\frac{1}{8}\right)-3\left(-\frac{1}{2}\right)^{2}+4\left(-\frac{1}{2}\right)+3$$

Express 2\left(-\frac{1}{8}\right) as a single fraction.

$$\frac{2\left(-1\right)}{8}-3\left(-\frac{1}{2}\right)^{2}+4\left(-\frac{1}{2}\right)+3$$

Multiply 2 and -1 to get -2.

$$\frac{-2}{8}-3\left(-\frac{1}{2}\right)^{2}+4\left(-\frac{1}{2}\right)+3$$

Reduce the fraction \frac{-2}{8} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{4}-3\left(-\frac{1}{2}\right)^{2}+4\left(-\frac{1}{2}\right)+3$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$-\frac{1}{4}-3\times \frac{1}{4}+4\left(-\frac{1}{2}\right)+3$$

Multiply 3 and \frac{1}{4} to get \frac{3}{4}.

$$-\frac{1}{4}-\frac{3}{4}+4\left(-\frac{1}{2}\right)+3$$

Since -\frac{1}{4} and \frac{3}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-1-3}{4}+4\left(-\frac{1}{2}\right)+3$$

Subtract 3 from -1 to get -4.

$$\frac{-4}{4}+4\left(-\frac{1}{2}\right)+3$$

Divide -4 by 4 to get -1.

$$-1+4\left(-\frac{1}{2}\right)+3$$

Express 4\left(-\frac{1}{2}\right) as a single fraction.

$$-1+\frac{4\left(-1\right)}{2}+3$$

Multiply 4 and -1 to get -4.

$$-1+\frac{-4}{2}+3$$

Divide -4 by 2 to get -2.

$$-1-2+3$$

Subtract 2 from -1 to get -3.

$$-3+3$$

Add -3 and 3 to get 0.

$$0$$

Factor

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