Solve =2^6=64quad(2)(-3/2)^6div(-3/2)^2

$$= 2 ^ { 6 } = 64 \quad ( 2 ) ( - \frac { 3 } { 2 } ) ^ { 6 } \div ( - \frac { 3 } { 2 } ) ^ { 2 }$$

Verify

Solution Steps

Calculate 2 to the power of 6 and get 64.

$$64=\frac{64\times 2\left(-\frac{3}{2}\right)^{6}}{\left(-\frac{3}{2}\right)^{2}}$$

Cancel out \left(-\frac{3}{2}\right)^{2} in both numerator and denominator.

$$64=2\times 64\left(-\frac{3}{2}\right)^{4}$$

Multiply 2 and 64 to get 128.

$$64=128\left(-\frac{3}{2}\right)^{4}$$

Calculate -\frac{3}{2} to the power of 4 and get \frac{81}{16}.

$$64=128\times \frac{81}{16}$$

Express 128\times \frac{81}{16} as a single fraction.

$$64=\frac{128\times 81}{16}$$

Multiply 128 and 81 to get 10368.

$$64=\frac{10368}{16}$$

Divide 10368 by 16 to get 648.

$$64=648$$

Compare 64 and 648.

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