Solve =1,3*xgeq29+x

$$= 1,3 \times x \geq 29 + x$$

Solve for x

$$x\geq \frac{290}{3}$$

Solution Steps

Subtract x from both sides.

$$1.3x-x\geq 29$$

Combine 1.3x and -x to get 0.3x.

$$0.3x\geq 29$$

Divide both sides by 0.3. Since 0.3 is positive, the inequality direction remains the same.

$$x\geq \frac{29}{0.3}$$

Expand \frac{29}{0.3} by multiplying both numerator and the denominator by 10.

$$x\geq \frac{290}{3}$$