Solve =1^2-4*(-32/4225)(220)

$$= 1 ^ { 2 } - 4 \cdot ( - \frac { 32 } { 4225 } ) ( 220 )$$

Evaluate

$$\frac{6477}{845}\approx 7.665088757$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$1-4\left(-\frac{32}{4225}\right)\times 220$$

Express 4\left(-\frac{32}{4225}\right) as a single fraction.

$$1-\frac{4\left(-32\right)}{4225}\times 220$$

Multiply 4 and -32 to get -128.

$$1-\frac{-128}{4225}\times 220$$

Fraction \frac{-128}{4225} can be rewritten as -\frac{128}{4225} by extracting the negative sign.

$$1-\left(-\frac{128}{4225}\times 220\right)$$

Express -\frac{128}{4225}\times 220 as a single fraction.

$$1-\frac{-128\times 220}{4225}$$

Multiply -128 and 220 to get -28160.

$$1-\frac{-28160}{4225}$$

Reduce the fraction \frac{-28160}{4225} to lowest terms by extracting and canceling out 5.

$$1-\left(-\frac{5632}{845}\right)$$

The opposite of -\frac{5632}{845} is \frac{5632}{845}.

$$1+\frac{5632}{845}$$

Convert 1 to fraction \frac{845}{845}.

$$\frac{845}{845}+\frac{5632}{845}$$

Since \frac{845}{845} and \frac{5632}{845} have the same denominator, add them by adding their numerators.

$$\frac{845+5632}{845}$$

Add 845 and 5632 to get 6477.

$$\frac{6477}{845}$$

Factor

$$\frac{3 \cdot 17 \cdot 127}{5 \cdot 13 ^ {2}} = 7\frac{562}{845} = 7.6650887573964495$$