Solve =0.2*(11/33)^2*[50*10^3/30*10^3]

$$= 0.2 \times ( \frac { 11 } { 33 } ) ^ { 2 } \times [ \frac { 50 \times 10 ^ { 3 } } { 30 \times 10 ^ { 3 } } ]$$

Evaluate

$$\frac{1}{27}\approx 0.037037037$$

Solution Steps

Reduce the fraction \frac{11}{33} to lowest terms by extracting and canceling out 11.

$$0.2\times \left(\frac{1}{3}\right)^{2}\times \frac{50\times 10^{3}}{30\times 10^{3}}$$

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$0.2\times \frac{1}{9}\times \frac{50\times 10^{3}}{30\times 10^{3}}$$

Multiply 0.2 and \frac{1}{9} to get \frac{1}{45}.

$$\frac{1}{45}\times \frac{50\times 10^{3}}{30\times 10^{3}}$$

Cancel out 10\times 10^{3} in both numerator and denominator.

$$\frac{1}{45}\times \frac{5}{3}$$

Multiply \frac{1}{45} and \frac{5}{3} to get \frac{1}{27}.

$$\frac{1}{27}$$

Factor

$$\frac{1}{3 ^ {3}} = 0.037037037037037035$$