Solve =0.2[600+(6/60)^2*1000]*9.807

$$= 0.2 [ 600 + ( \frac { 6 } { 60 } ) ^ { 2 } \times 1000 ] \times 9.807$$

Evaluate

$$1196.454$$

Solution Steps

Reduce the fraction \frac{6}{60} to lowest terms by extracting and canceling out 6.

$$0.2\left(600+\left(\frac{1}{10}\right)^{2}\times 1000\right)\times 9.807$$

Calculate \frac{1}{10} to the power of 2 and get \frac{1}{100}.

$$0.2\left(600+\frac{1}{100}\times 1000\right)\times 9.807$$

Multiply \frac{1}{100} and 1000 to get 10.

$$0.2\left(600+10\right)\times 9.807$$

Add 600 and 10 to get 610.

$$0.2\times 610\times 9.807$$

Multiply 0.2 and 610 to get 122.

$$122\times 9.807$$

Multiply 122 and 9.807 to get 1196.454.

$$1196.454$$

Factor

$$\frac{3 \cdot 7 \cdot 61 \cdot 467}{2 ^ {2} \cdot 5 ^ {3}} = 1196\frac{227}{500} = 1196.454$$