Solve for x
x=\frac{3y-7}{4}
Solve for y
y=\frac{4x+7}{3}
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-7-4x+3y=0
Subtract 7 from 0 to get -7.
-4x+3y=7
Add 7 to both sides. Anything plus zero gives itself.
-4x=7-3y
Subtract 3y from both sides.
\frac{-4x}{-4}=\frac{7-3y}{-4}
Divide both sides by -4.
x=\frac{7-3y}{-4}
Dividing by -4 undoes the multiplication by -4.
x=\frac{3y-7}{4}
Divide 7-3y by -4.
-7-4x+3y=0
Subtract 7 from 0 to get -7.
-4x+3y=7
Add 7 to both sides. Anything plus zero gives itself.
3y=7+4x
Add 4x to both sides.
3y=4x+7
The equation is in standard form.
\frac{3y}{3}=\frac{4x+7}{3}
Divide both sides by 3.
y=\frac{4x+7}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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