Solve =-13/4-61/3-2.25+10/3

$$= - 1 \frac { 3 } { 4 } - 6 \frac { 1 } { 3 } - 2.25 + \frac { 10 } { 3 }$$

Evaluate

$$-7$$

Solution Steps

Multiply 1 and 4 to get 4.

$$-\frac{4+3}{4}-\frac{6\times 3+1}{3}-2.25+\frac{10}{3}$$

Add 4 and 3 to get 7.

$$-\frac{7}{4}-\frac{6\times 3+1}{3}-2.25+\frac{10}{3}$$

Multiply 6 and 3 to get 18.

$$-\frac{7}{4}-\frac{18+1}{3}-2.25+\frac{10}{3}$$

Add 18 and 1 to get 19.

$$-\frac{7}{4}-\frac{19}{3}-2.25+\frac{10}{3}$$

Least common multiple of 4 and 3 is 12. Convert -\frac{7}{4} and \frac{19}{3} to fractions with denominator 12.

$$-\frac{21}{12}-\frac{76}{12}-2.25+\frac{10}{3}$$

Since -\frac{21}{12} and \frac{76}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-21-76}{12}-2.25+\frac{10}{3}$$

Subtract 76 from -21 to get -97.

$$-\frac{97}{12}-2.25+\frac{10}{3}$$

Convert decimal number 2.25 to fraction \frac{225}{100}. Reduce the fraction \frac{225}{100} to lowest terms by extracting and canceling out 25.

$$-\frac{97}{12}-\frac{9}{4}+\frac{10}{3}$$

Least common multiple of 12 and 4 is 12. Convert -\frac{97}{12} and \frac{9}{4} to fractions with denominator 12.

$$-\frac{97}{12}-\frac{27}{12}+\frac{10}{3}$$

Since -\frac{97}{12} and \frac{27}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-97-27}{12}+\frac{10}{3}$$

Subtract 27 from -97 to get -124.

$$\frac{-124}{12}+\frac{10}{3}$$

Reduce the fraction \frac{-124}{12} to lowest terms by extracting and canceling out 4.

$$-\frac{31}{3}+\frac{10}{3}$$

Since -\frac{31}{3} and \frac{10}{3} have the same denominator, add them by adding their numerators.

$$\frac{-31+10}{3}$$

Add -31 and 10 to get -21.

$$\frac{-21}{3}$$

Divide -21 by 3 to get -7.

$$-7$$

Factor

$$-7$$