Solve =-33/4+1+16+1

$$= - \frac { 33 } { 4 } + 1 + 16 + 1$$

Evaluate

$$\frac{39}{4}=9.75$$

Solution Steps

Convert 1 to fraction \frac{4}{4}.

$$-\frac{33}{4}+\frac{4}{4}+16+1$$

Since -\frac{33}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.

$$\frac{-33+4}{4}+16+1$$

Add -33 and 4 to get -29.

$$-\frac{29}{4}+16+1$$

Convert 16 to fraction \frac{64}{4}.

$$-\frac{29}{4}+\frac{64}{4}+1$$

Since -\frac{29}{4} and \frac{64}{4} have the same denominator, add them by adding their numerators.

$$\frac{-29+64}{4}+1$$

Add -29 and 64 to get 35.

$$\frac{35}{4}+1$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{35}{4}+\frac{4}{4}$$

Since \frac{35}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.

$$\frac{35+4}{4}$$

Add 35 and 4 to get 39.

$$\frac{39}{4}$$

Factor

$$\frac{3 \cdot 13}{2 ^ {2}} = 9\frac{3}{4} = 9.75$$