Solve =(5-7/5)^2+(1+4/5)^2

$$= ( 5 - \frac { 7 } { 5 } ) ^ { 2 } + ( 1 + \frac { 4 } { 5 } ) ^ { 2 }$$

Evaluate

$$\frac{81}{5}=16.2$$

Solution Steps

Subtract \frac{7}{5} from 5 to get \frac{18}{5}.

$$\left(\frac{18}{5}\right)^{2}+\left(1+\frac{4}{5}\right)^{2}$$

Calculate \frac{18}{5} to the power of 2 and get \frac{324}{25}.

$$\frac{324}{25}+\left(1+\frac{4}{5}\right)^{2}$$

Add 1 and \frac{4}{5} to get \frac{9}{5}.

$$\frac{324}{25}+\left(\frac{9}{5}\right)^{2}$$

Calculate \frac{9}{5} to the power of 2 and get \frac{81}{25}.

$$\frac{324}{25}+\frac{81}{25}$$

Add \frac{324}{25} and \frac{81}{25} to get \frac{81}{5}.

$$\frac{81}{5}$$

Factor

$$\frac{3 ^ {4}}{5} = 16\frac{1}{5} = 16.2$$