Evaluate
12\sqrt{5}+49\approx 75.83281573
Expand
12 \sqrt{5} + 49 = 75.83281573
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9\left(\sqrt{5}\right)^{2}+12\sqrt{5}+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3\sqrt{5}+2\right)^{2}.
9\times 5+12\sqrt{5}+4
The square of \sqrt{5} is 5.
45+12\sqrt{5}+4
Multiply 9 and 5 to get 45.
49+12\sqrt{5}
Add 45 and 4 to get 49.
9\left(\sqrt{5}\right)^{2}+12\sqrt{5}+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(3\sqrt{5}+2\right)^{2}.
9\times 5+12\sqrt{5}+4
The square of \sqrt{5} is 5.
45+12\sqrt{5}+4
Multiply 9 and 5 to get 45.
49+12\sqrt{5}
Add 45 and 4 to get 49.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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