Solve =(3^-10*7*2^-3)^2

$$= ( 3 ^ { - 10 } \times 7 \times 2 ^ { - 3 } ) ^ { 2 }$$

Evaluate

$$\frac{49}{223154201664}\approx 2.195791055 \cdot 10^{-10}$$

Solution Steps

Calculate 3 to the power of -10 and get \frac{1}{59049}.

$$\left(\frac{1}{59049}\times 7\times 2^{-3}\right)^{2}$$

Multiply \frac{1}{59049} and 7 to get \frac{7}{59049}.

$$\left(\frac{7}{59049}\times 2^{-3}\right)^{2}$$

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\left(\frac{7}{59049}\times \frac{1}{8}\right)^{2}$$

Multiply \frac{7}{59049} and \frac{1}{8} to get \frac{7}{472392}.

$$\left(\frac{7}{472392}\right)^{2}$$

Calculate \frac{7}{472392} to the power of 2 and get \frac{49}{223154201664}.

$$\frac{49}{223154201664}$$

Factor

$$\frac{7 ^ {2}}{2 ^ {6} \cdot 3 ^ {20}} = 2.1957910554504627 \times 10^{-10}$$