Solve =(-2-0)^2*4/2+(0*0)^2*3/9+(1*0)

$$= ( - 2 - 0 ) ^ { 2 } \times \frac { 4 } { 2 } + ( 0 \times 0 ) ^ { 2 } \times \frac { 3 } { 9 } + ( 1 \times 0 )$$

Evaluate

$$8$$

Solution Steps

Subtract 0 from -2 to get -2.

$$\left(-2\right)^{2}\times \frac{4}{2}+\left(0\times 0\right)^{2}\times \frac{3}{9}+1\times 0$$

Calculate -2 to the power of 2 and get 4.

$$4\times \frac{4}{2}+\left(0\times 0\right)^{2}\times \frac{3}{9}+1\times 0$$

Divide 4 by 2 to get 2.

$$4\times 2+\left(0\times 0\right)^{2}\times \frac{3}{9}+1\times 0$$

Multiply 4 and 2 to get 8.

$$8+\left(0\times 0\right)^{2}\times \frac{3}{9}+1\times 0$$

Multiply 0 and 0 to get 0.

$$8+0^{2}\times \frac{3}{9}+1\times 0$$

Calculate 0 to the power of 2 and get 0.

$$8+0\times \frac{3}{9}+1\times 0$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$8+0\times \frac{1}{3}+1\times 0$$

Multiply 0 and \frac{1}{3} to get 0.

$$8+0+1\times 0$$

Add 8 and 0 to get 8.

$$8+1\times 0$$

Multiply 1 and 0 to get 0.

$$8+0$$

Add 8 and 0 to get 8.

$$8$$

Factor

$$2^{3}$$