Solve =(-2)^5+(-2)^6+(-2/2)^7+(-2)^8

$$= ( - 2 ) ^ { 5 } + ( - 2 ) ^ { 6 } + ( - \frac { 2 } { 2 } ) ^ { 7 } + ( - 2 ) ^ { 8 }$$

Evaluate

$$287$$

Solution Steps

Divide 2 by 2 to get 1.

$$\left(-2\right)^{5}+\left(-2\right)^{6}+\left(-1\right)^{7}+\left(-2\right)^{8}$$

Calculate -2 to the power of 5 and get -32.

$$-32+\left(-2\right)^{6}+\left(-1\right)^{7}+\left(-2\right)^{8}$$

Calculate -2 to the power of 6 and get 64.

$$-32+64+\left(-1\right)^{7}+\left(-2\right)^{8}$$

Add -32 and 64 to get 32.

$$32+\left(-1\right)^{7}+\left(-2\right)^{8}$$

Calculate -1 to the power of 7 and get -1.

$$32-1+\left(-2\right)^{8}$$

Subtract 1 from 32 to get 31.

$$31+\left(-2\right)^{8}$$

Calculate -2 to the power of 8 and get 256.

$$31+256$$

Add 31 and 256 to get 287.

$$287$$

Factor

$$7\times 41$$