Solve =(-1/3)^2+sqrt{64/81}-(3/7)^2pi0=0

$$= ( - \frac { 1 } { 3 } ) ^ { 2 } + \sqrt { \frac { 64 } { 81 } } - ( \frac { 3 } { 7 } ) ^ { 2 \pi 0 } = 0$$

Verify

Solution Steps

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{1}{9}+\sqrt{\frac{64}{81}}-\left(\frac{3}{7}\right)^{2\pi \times 0}=0$$

Rewrite the square root of the division \frac{64}{81} as the division of square roots \frac{\sqrt{64}}{\sqrt{81}}. Take the square root of both numerator and denominator.

$$\frac{1}{9}+\frac{8}{9}-\left(\frac{3}{7}\right)^{2\pi \times 0}=0$$

Add \frac{1}{9} and \frac{8}{9} to get 1.

$$1-\left(\frac{3}{7}\right)^{2\pi \times 0}=0$$

Multiply 2 and 0 to get 0.

$$1-\left(\frac{3}{7}\right)^{0\pi }=0$$

Anything times zero gives zero.

$$1-\left(\frac{3}{7}\right)^{0}=0$$

Calculate \frac{3}{7} to the power of 0 and get 1.

$$1-1=0$$

Subtract 1 from 1 to get 0.

$$0=0$$

Compare 0 and 0.

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