Solve =(1/2+2/2*15/5)-9/2=frac{3}{2}

$$= ( \frac { 1 } { 2 } + \frac { 2 } { 2 } \times \frac { 15 } { 5 } ) - \frac { 9 } { 2 } = \frac { 3 } { 2 }$$

Verify

Solution Steps

Divide 2 by 2 to get 1.

$$\frac{1}{2}+1\times \frac{15}{5}-\frac{9}{2}=\frac{3}{2}$$

Divide 15 by 5 to get 3.

$$\frac{1}{2}+1\times 3-\frac{9}{2}=\frac{3}{2}$$

Multiply 1 and 3 to get 3.

$$\frac{1}{2}+3-\frac{9}{2}=\frac{3}{2}$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{1}{2}+\frac{6}{2}-\frac{9}{2}=\frac{3}{2}$$

Since \frac{1}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$\frac{1+6}{2}-\frac{9}{2}=\frac{3}{2}$$

Add 1 and 6 to get 7.

$$\frac{7}{2}-\frac{9}{2}=\frac{3}{2}$$

Since \frac{7}{2} and \frac{9}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-9}{2}=\frac{3}{2}$$

Subtract 9 from 7 to get -2.

$$\frac{-2}{2}=\frac{3}{2}$$

Divide -2 by 2 to get -1.

$$-1=\frac{3}{2}$$

Convert -1 to fraction -\frac{2}{2}.

$$-\frac{2}{2}=\frac{3}{2}$$

Compare -\frac{2}{2} and \frac{3}{2}.

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