Solve =sqrt[3]{2^2*2^3}-(3^2)^2+3*(-7)]:(-1)=

$$= \sqrt[ 3 ] { 2 ^ { 2 } \cdot 2 ^ { 3 } } - ( 3 ^ { 2 } ) ^ { 2 } + 3 \cdot ( - 7 ) ] : ( - 1 ) =$$

Evaluate

$$2^{\frac{5}{3}}-102\approx -98.825197896$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$\sqrt[3]{2^{5}}-\left(3^{2}\right)^{2}+3\left(-7\right)$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$\sqrt[3]{2^{5}}-3^{4}+3\left(-7\right)$$

Calculate 2 to the power of 5 and get 32.

$$\sqrt[3]{32}-3^{4}+3\left(-7\right)$$

Calculate 3 to the power of 4 and get 81.

$$\sqrt[3]{32}-81+3\left(-7\right)$$

Multiply 3 and -7 to get -21.

$$\sqrt[3]{32}-81-21$$

Subtract 21 from -81 to get -102.

$$\sqrt[3]{32}-102$$