Solve =pi[(32(4)-6(4)^2+(4)^3/3)-0]

$$= \pi [ ( 32 ( 4 ) - 6 ( 4 ) ^ { 2 } + \frac { ( 4 ) ^ { 3 } } { 3 } ) - 0 ]$$

Evaluate

$$\frac{160\pi }{3}\approx 167.551608191$$

Solution Steps

Multiply 32 and 4 to get 128.

$$\pi \left(128-6\times 4^{2}+\frac{4^{3}}{3}-0\right)$$

Calculate 4 to the power of 2 and get 16.

$$\pi \left(128-6\times 16+\frac{4^{3}}{3}-0\right)$$

Multiply 6 and 16 to get 96.

$$\pi \left(128-96+\frac{4^{3}}{3}-0\right)$$

Subtract 96 from 128 to get 32.

$$\pi \left(32+\frac{4^{3}}{3}-0\right)$$

Calculate 4 to the power of 3 and get 64.

$$\pi \left(32+\frac{64}{3}-0\right)$$

Convert 32 to fraction \frac{96}{3}.

$$\pi \left(\frac{96}{3}+\frac{64}{3}-0\right)$$

Since \frac{96}{3} and \frac{64}{3} have the same denominator, add them by adding their numerators.

$$\pi \left(\frac{96+64}{3}-0\right)$$

Add 96 and 64 to get 160.

$$\pi \left(\frac{160}{3}-0\right)$$

Subtract 0 from \frac{160}{3} to get \frac{160}{3}.

$$\pi \times \frac{160}{3}$$

Expand

$$\frac{160 \pi}{3} = 167.55160819145564$$

Solution Steps

Multiply 32 and 4 to get 128.

$$\pi \left(128-6\times 4^{2}+\frac{4^{3}}{3}-0\right)$$

Calculate 4 to the power of 2 and get 16.

$$\pi \left(128-6\times 16+\frac{4^{3}}{3}-0\right)$$

Multiply 6 and 16 to get 96.

$$\pi \left(128-96+\frac{4^{3}}{3}-0\right)$$

Subtract 96 from 128 to get 32.

$$\pi \left(32+\frac{4^{3}}{3}-0\right)$$

Calculate 4 to the power of 3 and get 64.

$$\pi \left(32+\frac{64}{3}-0\right)$$

Convert 32 to fraction \frac{96}{3}.

$$\pi \left(\frac{96}{3}+\frac{64}{3}-0\right)$$

Since \frac{96}{3} and \frac{64}{3} have the same denominator, add them by adding their numerators.

$$\pi \left(\frac{96+64}{3}-0\right)$$

Add 96 and 64 to get 160.

$$\pi \left(\frac{160}{3}-0\right)$$

Subtract 0 from \frac{160}{3} to get \frac{160}{3}.

$$\pi \times \frac{160}{3}$$