Solve = ∫ (4*79*10^-4)^2*54*3

$$= \int ( 4 \cdot 79 \times 10 ^ { - 4 } ) ^ { 2 } \times 54 \cdot 3$$

Evaluate

$$\frac{505521x}{3125000}+С$$

Solution Steps

Multiply 4 and 79 to get 316.

$$\int \left(316\times 10^{-4}\right)^{2}\times 54\times 3\mathrm{d}x$$

Calculate 10 to the power of -4 and get \frac{1}{10000}.

$$\int \left(316\times \frac{1}{10000}\right)^{2}\times 54\times 3\mathrm{d}x$$

Multiply 316 and \frac{1}{10000} to get \frac{79}{2500}.

$$\int \left(\frac{79}{2500}\right)^{2}\times 54\times 3\mathrm{d}x$$

Calculate \frac{79}{2500} to the power of 2 and get \frac{6241}{6250000}.

$$\int \frac{6241}{6250000}\times 54\times 3\mathrm{d}x$$

Multiply \frac{6241}{6250000} and 54 to get \frac{168507}{3125000}.

$$\int \frac{168507}{3125000}\times 3\mathrm{d}x$$

Multiply \frac{168507}{3125000} and 3 to get \frac{505521}{3125000}.

$$\int \frac{505521}{3125000}\mathrm{d}x$$

Find the integral of \frac{505521}{3125000} using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\frac{505521x}{3125000}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{505521x}{3125000}+С$$

Differentiate w.r.t. x

$$\frac{505521}{3125000} = 0.16176672$$