Solve =8/3+4-1--2/3+(-4)-(-2)

$$= \frac { 8 } { 3 } + 4 - 1 - \frac { - 2 } { 3 } + ( - 4 ) - ( - 2 )$$

Evaluate

$$\frac{13}{3}\approx 4.333333333$$

Solution Steps

Convert 4 to fraction \frac{12}{3}.

$$\frac{8}{3}+\frac{12}{3}-1-\frac{-2}{3}-4-\left(-2\right)$$

Since \frac{8}{3} and \frac{12}{3} have the same denominator, add them by adding their numerators.

$$\frac{8+12}{3}-1-\frac{-2}{3}-4-\left(-2\right)$$

Add 8 and 12 to get 20.

$$\frac{20}{3}-1-\frac{-2}{3}-4-\left(-2\right)$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{20}{3}-\frac{3}{3}-\frac{-2}{3}-4-\left(-2\right)$$

Since \frac{20}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{20-3}{3}-\frac{-2}{3}-4-\left(-2\right)$$

Subtract 3 from 20 to get 17.

$$\frac{17}{3}-\frac{-2}{3}-4-\left(-2\right)$$

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$\frac{17}{3}-\left(-\frac{2}{3}\right)-4-\left(-2\right)$$

The opposite of -\frac{2}{3} is \frac{2}{3}.

$$\frac{17}{3}+\frac{2}{3}-4-\left(-2\right)$$

Since \frac{17}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{17+2}{3}-4-\left(-2\right)$$

Add 17 and 2 to get 19.

$$\frac{19}{3}-4-\left(-2\right)$$

Convert 4 to fraction \frac{12}{3}.

$$\frac{19}{3}-\frac{12}{3}-\left(-2\right)$$

Since \frac{19}{3} and \frac{12}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{19-12}{3}-\left(-2\right)$$

Subtract 12 from 19 to get 7.

$$\frac{7}{3}-\left(-2\right)$$

The opposite of -2 is 2.

$$\frac{7}{3}+2$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{7}{3}+\frac{6}{3}$$

Since \frac{7}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{7+6}{3}$$

Add 7 and 6 to get 13.

$$\frac{13}{3}$$

Factor

$$\frac{13}{3} = 4\frac{1}{3} = 4.333333333333333$$