Solve =7-10+3/sqrt{49+25+1sqrt{1+4+9}}

$$= \frac { 7 - 10 + 3 } { \sqrt { 49 + 25 + 1 } \sqrt { 1 + 4 + 9 } }$$

Evaluate

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Solution Steps

Subtract 10 from 7 to get -3.

$$\frac{-3+3}{\sqrt{49+25+1}\sqrt{1+4+9}}$$

Add -3 and 3 to get 0.

$$\frac{0}{\sqrt{49+25+1}\sqrt{1+4+9}}$$

Add 49 and 25 to get 74.

$$\frac{0}{\sqrt{74+1}\sqrt{1+4+9}}$$

Add 74 and 1 to get 75.

$$\frac{0}{\sqrt{75}\sqrt{1+4+9}}$$

Factor 75=5^{2}\times 3. Rewrite the square root of the product \sqrt{5^{2}\times 3} as the product of square roots \sqrt{5^{2}}\sqrt{3}. Take the square root of 5^{2}.

$$\frac{0}{5\sqrt{3}\sqrt{1+4+9}}$$

Add 1 and 4 to get 5.

$$\frac{0}{5\sqrt{3}\sqrt{5+9}}$$

Add 5 and 9 to get 14.

$$\frac{0}{5\sqrt{3}\sqrt{14}}$$

To multiply \sqrt{3} and \sqrt{14}, multiply the numbers under the square root.

$$\frac{0}{5\sqrt{42}}$$

Zero divided by any non-zero term gives zero.

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Factor

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