Solve =4/721/3+1/4=4+3/12=frac{7}{7}

$$= \frac { 4 } { 72 } \frac { 1 } { 3 } + \frac { 1 } { 4 } = \frac { 4 + 3 } { 12 } = \frac { 7 } { 7 }$$

Verify

Solution Steps

Divide 7 by 7 to get 1.

$$\frac{4}{72}\times \frac{1}{3}+\frac{1}{4}=\frac{4+3}{12}\text{ and }\frac{4+3}{12}=1$$

Reduce the fraction \frac{4}{72} to lowest terms by extracting and canceling out 4.

$$\frac{1}{18}\times \frac{1}{3}+\frac{1}{4}=\frac{4+3}{12}\text{ and }\frac{4+3}{12}=1$$

Multiply \frac{1}{18} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 1}{18\times 3}+\frac{1}{4}=\frac{4+3}{12}\text{ and }\frac{4+3}{12}=1$$

Do the multiplications in the fraction \frac{1\times 1}{18\times 3}.

$$\frac{1}{54}+\frac{1}{4}=\frac{4+3}{12}\text{ and }\frac{4+3}{12}=1$$

Least common multiple of 54 and 4 is 108. Convert \frac{1}{54} and \frac{1}{4} to fractions with denominator 108.

$$\frac{2}{108}+\frac{27}{108}=\frac{4+3}{12}\text{ and }\frac{4+3}{12}=1$$

Since \frac{2}{108} and \frac{27}{108} have the same denominator, add them by adding their numerators.

$$\frac{2+27}{108}=\frac{4+3}{12}\text{ and }\frac{4+3}{12}=1$$

Add 2 and 27 to get 29.

$$\frac{29}{108}=\frac{4+3}{12}\text{ and }\frac{4+3}{12}=1$$

Add 4 and 3 to get 7.

$$\frac{29}{108}=\frac{7}{12}\text{ and }\frac{4+3}{12}=1$$

Least common multiple of 108 and 12 is 108. Convert \frac{29}{108} and \frac{7}{12} to fractions with denominator 108.

$$\frac{29}{108}=\frac{63}{108}\text{ and }\frac{4+3}{12}=1$$

Compare \frac{29}{108} and \frac{63}{108}.

$$\text{false}\text{ and }\frac{4+3}{12}=1$$

Add 4 and 3 to get 7.

$$\text{false}\text{ and }\frac{7}{12}=1$$

Convert 1 to fraction \frac{12}{12}.

$$\text{false}\text{ and }\frac{7}{12}=\frac{12}{12}$$

Compare \frac{7}{12} and \frac{12}{12}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$