Solve =16*1(3*(0*5)^2+(1)^2)/32*2*12

$$= \frac { 16 \cdot 1 ( 3 \times ( 0 \cdot 5 ) ^ { 2 } + ( 1 ) ^ { 2 } ) } { 32 \cdot 2 \times 12 }$$

Evaluate

$$\frac{1}{48}\approx 0.020833333$$

Solution Steps

Cancel out 16 in both numerator and denominator.

$$\frac{3\times 0^{2}+1^{2}}{2\times 2\times 12}$$

Calculate 0 to the power of 2 and get 0.

$$\frac{3\times 0+1^{2}}{2\times 2\times 12}$$

Multiply 3 and 0 to get 0.

$$\frac{0+1^{2}}{2\times 2\times 12}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{0+1}{2\times 2\times 12}$$

Add 0 and 1 to get 1.

$$\frac{1}{2\times 2\times 12}$$

Multiply 2 and 2 to get 4.

$$\frac{1}{4\times 12}$$

Multiply 4 and 12 to get 48.

$$\frac{1}{48}$$

Factor

$$\frac{1}{2 ^ {4} \cdot 3} = 0.020833333333333332$$