Verify
true
Share
Copied to clipboard
\frac{125}{1000}=\frac{125}{1000}\text{ and }\frac{125}{1000}=\frac{1}{8}
Expand \frac{12.5}{100} by multiplying both numerator and the denominator by 10.
\frac{1}{8}=\frac{125}{1000}\text{ and }\frac{125}{1000}=\frac{1}{8}
Reduce the fraction \frac{125}{1000} to lowest terms by extracting and canceling out 125.
\frac{1}{8}=\frac{1}{8}\text{ and }\frac{125}{1000}=\frac{1}{8}
Reduce the fraction \frac{125}{1000} to lowest terms by extracting and canceling out 125.
\text{true}\text{ and }\frac{125}{1000}=\frac{1}{8}
Compare \frac{1}{8} and \frac{1}{8}.
\text{true}\text{ and }\frac{1}{8}=\frac{1}{8}
Reduce the fraction \frac{125}{1000} to lowest terms by extracting and canceling out 125.
\text{true}\text{ and }\text{true}
Compare \frac{1}{8} and \frac{1}{8}.
\text{true}
The conjunction of \text{true} and \text{true} is \text{true}.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}