Solve =1-(1+3,9%)^-3/3,9

$$= \frac { 1 - ( 1 + 3,9 \% ) ^ { - 3 } } { 3,9 }$$

Evaluate

$$\frac{31185210}{1121622319}\approx 0.027803664$$

Solution Steps

Expand \frac{3.9}{100} by multiplying both numerator and the denominator by 10.

$$\frac{1-\left(1+\frac{39}{1000}\right)^{-3}}{3.9}$$

Add 1 and \frac{39}{1000} to get \frac{1039}{1000}.

$$\frac{1-\left(\frac{1039}{1000}\right)^{-3}}{3.9}$$

Calculate \frac{1039}{1000} to the power of -3 and get \frac{1000000000}{1121622319}.

$$\frac{1-\frac{1000000000}{1121622319}}{3.9}$$

Subtract \frac{1000000000}{1121622319} from 1 to get \frac{121622319}{1121622319}.

$$\frac{\frac{121622319}{1121622319}}{3.9}$$

Express \frac{\frac{121622319}{1121622319}}{3.9} as a single fraction.

$$\frac{121622319}{1121622319\times 3.9}$$

Multiply 1121622319 and 3.9 to get 4374327044.1.

$$\frac{121622319}{4374327044.1}$$

Expand \frac{121622319}{4374327044.1} by multiplying both numerator and the denominator by 10.

$$\frac{1216223190}{43743270441}$$

Reduce the fraction \frac{1216223190}{43743270441} to lowest terms by extracting and canceling out 39.

$$\frac{31185210}{1121622319}$$

Factor

$$\frac{2 \cdot 3 \cdot 5 \cdot 7 \cdot 148501}{1039 ^ {3}} = 0.027803663917639998$$