Solve =1/2(4/512+23/256)

$$= \frac { 1 } { 2 } ( \frac { 4 } { 512 } + \frac { 23 } { 256 } )$$

Evaluate

$$\frac{25}{512}=0.048828125$$

Solution Steps

Reduce the fraction \frac{4}{512} to lowest terms by extracting and canceling out 4.

$$\frac{1}{2}\left(\frac{1}{128}+\frac{23}{256}\right)$$

Least common multiple of 128 and 256 is 256. Convert \frac{1}{128} and \frac{23}{256} to fractions with denominator 256.

$$\frac{1}{2}\left(\frac{2}{256}+\frac{23}{256}\right)$$

Since \frac{2}{256} and \frac{23}{256} have the same denominator, add them by adding their numerators.

$$\frac{1}{2}\times \frac{2+23}{256}$$

Add 2 and 23 to get 25.

$$\frac{1}{2}\times \frac{25}{256}$$

Multiply \frac{1}{2} times \frac{25}{256} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 25}{2\times 256}$$

Do the multiplications in the fraction \frac{1\times 25}{2\times 256}.

$$\frac{25}{512}$$

Factor

$$\frac{5 ^ {2}}{2 ^ {9}} = 0.048828125$$