Solve =(a-b)(a^2-9b^2)/(a^2+3ab)(a^2-ab)

$$= \frac { ( a - b ) ( a ^ { 2 } - 9 b ^ { 2 } ) } { ( a ^ { 2 } + 3 a b ) ( a ^ { 2 } - a b ) }$$

Evaluate

$$\frac{a-3b}{a^{2}}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{\left(a-3b\right)\left(a-b\right)\left(a+3b\right)}{\left(a-b\right)\left(a+3b\right)a^{2}}$$

Cancel out \left(a-b\right)\left(a+3b\right) in both numerator and denominator.

$$\frac{a-3b}{a^{2}}$$

Expand

$$\frac{a-3b}{a^{2}}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{\left(a-3b\right)\left(a-b\right)\left(a+3b\right)}{\left(a-b\right)\left(a+3b\right)a^{2}}$$

Cancel out \left(a-b\right)\left(a+3b\right) in both numerator and denominator.

$$\frac{a-3b}{a^{2}}$$