Solve =(6125*0.0022)(0.999)(87-68)+8.747/0.237+1.16

$$= \frac { ( 6125 \cdot 0.0022 ) ( 0.999 ) ( 87 - 68 ) + 8.747 } { 0.237 } + 1.16$$

Evaluate

$$\frac{52958179}{47400}\approx 1117.261160338$$

Solution Steps

Multiply 6125 and 0.0022 to get 13.475.

$$\frac{13.475\times 0.999\left(87-68\right)+8.747}{0.237}+1.16$$

Multiply 13.475 and 0.999 to get 13.461525.

$$\frac{13.461525\left(87-68\right)+8.747}{0.237}+1.16$$

Subtract 68 from 87 to get 19.

$$\frac{13.461525\times 19+8.747}{0.237}+1.16$$

Multiply 13.461525 and 19 to get 255.768975.

$$\frac{255.768975+8.747}{0.237}+1.16$$

Add 255.768975 and 8.747 to get 264.515975.

$$\frac{264.515975}{0.237}+1.16$$

Expand \frac{264.515975}{0.237} by multiplying both numerator and the denominator by 1000000.

$$\frac{264515975}{237000}+1.16$$

Reduce the fraction \frac{264515975}{237000} to lowest terms by extracting and canceling out 25.

$$\frac{10580639}{9480}+1.16$$

Convert decimal number 1.16 to fraction \frac{116}{100}. Reduce the fraction \frac{116}{100} to lowest terms by extracting and canceling out 4.

$$\frac{10580639}{9480}+\frac{29}{25}$$

Least common multiple of 9480 and 25 is 47400. Convert \frac{10580639}{9480} and \frac{29}{25} to fractions with denominator 47400.

$$\frac{52903195}{47400}+\frac{54984}{47400}$$

Since \frac{52903195}{47400} and \frac{54984}{47400} have the same denominator, add them by adding their numerators.

$$\frac{52903195+54984}{47400}$$

Add 52903195 and 54984 to get 52958179.

$$\frac{52958179}{47400}$$

Factor

$$\frac{17 \cdot 3115187}{3 \cdot 79 \cdot 2 ^ {3} \cdot 5 ^ {2}} = 1117\frac{12379}{47400} = 1117.2611603375528$$