Solve =frac{(4-3)(4+3)+8-sqrt{144}+(sqrt{36})^{2}+1^{2}}{(25)^{3}-(2^2-1^2)}-8-(-3^2+4)*(-2)+(2*5)+2^2/2-87

$$= \frac { ( 4 - 3 ) ( 4 + 3 ) + 8 - \sqrt { 144 } + ( \sqrt { 36 } ) ^ { 2 } + 1 ^ { 2 } } { ( 25 ) ^ { 3 } - ( 2 ^ { 2 } - 1 ^ { 2 } ) } - \frac { 8 - ( - 3 ^ { 2 } + 4 ) \cdot ( - 2 ) + ( 2 \cdot 5 ) + 2 ^ { 2 } } { 2 } - 87$$

Evaluate

$$-\frac{726403}{7811}\approx -92.997439508$$

Solution Steps

Subtract 3 from 4 to get 1.

$$\frac{1\left(4+3\right)+8-\sqrt{144}+\left(\sqrt{36}\right)^{2}+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Add 4 and 3 to get 7.

$$\frac{1\times 7+8-\sqrt{144}+\left(\sqrt{36}\right)^{2}+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Multiply 1 and 7 to get 7.

$$\frac{7+8-\sqrt{144}+\left(\sqrt{36}\right)^{2}+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Add 7 and 8 to get 15.

$$\frac{15-\sqrt{144}+\left(\sqrt{36}\right)^{2}+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Calculate the square root of 144 and get 12.

$$\frac{15-12+\left(\sqrt{36}\right)^{2}+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Subtract 12 from 15 to get 3.

$$\frac{3+\left(\sqrt{36}\right)^{2}+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

The square of \sqrt{36} is 36.

$$\frac{3+36+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Add 3 and 36 to get 39.

$$\frac{39+1^{2}}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Calculate 1 to the power of 2 and get 1.

$$\frac{39+1}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Add 39 and 1 to get 40.

$$\frac{40}{25^{3}-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Calculate 25 to the power of 3 and get 15625.

$$\frac{40}{15625-\left(2^{2}-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Calculate 2 to the power of 2 and get 4.

$$\frac{40}{15625-\left(4-1^{2}\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Calculate 1 to the power of 2 and get 1.

$$\frac{40}{15625-\left(4-1\right)}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Subtract 1 from 4 to get 3.

$$\frac{40}{15625-3}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Subtract 3 from 15625 to get 15622.

$$\frac{40}{15622}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Reduce the fraction \frac{40}{15622} to lowest terms by extracting and canceling out 2.

$$\frac{20}{7811}-\frac{8-\left(-3^{2}+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Calculate 3 to the power of 2 and get 9.

$$\frac{20}{7811}-\frac{8-\left(-9+4\right)\left(-2\right)+2\times 5+2^{2}}{2}-87$$

Add -9 and 4 to get -5.

$$\frac{20}{7811}-\frac{8-\left(-5\left(-2\right)\right)+2\times 5+2^{2}}{2}-87$$

Multiply -5 and -2 to get 10.

$$\frac{20}{7811}-\frac{8-10+2\times 5+2^{2}}{2}-87$$

Subtract 10 from 8 to get -2.

$$\frac{20}{7811}-\frac{-2+2\times 5+2^{2}}{2}-87$$

Multiply 2 and 5 to get 10.

$$\frac{20}{7811}-\frac{-2+10+2^{2}}{2}-87$$

Add -2 and 10 to get 8.

$$\frac{20}{7811}-\frac{8+2^{2}}{2}-87$$

Calculate 2 to the power of 2 and get 4.

$$\frac{20}{7811}-\frac{8+4}{2}-87$$

Add 8 and 4 to get 12.

$$\frac{20}{7811}-\frac{12}{2}-87$$

Divide 12 by 2 to get 6.

$$\frac{20}{7811}-6-87$$

Subtract 6 from \frac{20}{7811} to get -\frac{46846}{7811}.

$$-\frac{46846}{7811}-87$$

Subtract 87 from -\frac{46846}{7811} to get -\frac{726403}{7811}.

$$-\frac{726403}{7811}$$

Factor

$$-\frac{726403}{7811} = -92\frac{7791}{7811} = -92.99743950838561$$