Solve =frac{sqrt{3}}{2}-frac{sqrt{2}}{16}+1/4

$$= \frac { \sqrt { 3 } } { 2 } - \frac { \sqrt { 2 } } { 16 } + \frac { 1 } { 4 }$$

Evaluate

$$\frac{\sqrt{3}}{2}-\frac{\sqrt{2}}{16}+\frac{1}{4}\approx 1.027637056$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2 and 16 is 16. Multiply \frac{\sqrt{3}}{2} times \frac{8}{8}.

$$\frac{8\sqrt{3}}{16}-\frac{\sqrt{2}}{16}+\frac{1}{4}$$

Since \frac{8\sqrt{3}}{16} and \frac{\sqrt{2}}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8\sqrt{3}-\sqrt{2}}{16}+\frac{1}{4}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 16 and 4 is 16. Multiply \frac{1}{4} times \frac{4}{4}.

$$\frac{8\sqrt{3}-\sqrt{2}}{16}+\frac{4}{16}$$

Since \frac{8\sqrt{3}-\sqrt{2}}{16} and \frac{4}{16} have the same denominator, add them by adding their numerators.

$$\frac{8\sqrt{3}-\sqrt{2}+4}{16}$$

Factor

$$\frac{8 \sqrt{3} + 4 - \sqrt{2}}{16} = 1.02763705613612$$