Solve =frac{sqrt{25}}{sqrt{64}}+(256/625)^-1/4+1/(frac{64{125})}

$$= \frac { \sqrt { 25 } } { \sqrt { 64 } } + ( \frac { 256 } { 625 } ) ^ { - 1 / 4 } + \frac { 1 } { ( \frac { 64 } { 125 } ) }$$

Evaluate

$$\frac{245}{64}=3.828125$$

Solution Steps

Calculate the square root of 25 and get 5.

$$\frac{5}{\sqrt{64}}+\left(\frac{256}{625}\right)^{-\frac{1}{4}}+\frac{1}{\frac{64}{125}}$$

Calculate the square root of 64 and get 8.

$$\frac{5}{8}+\left(\frac{256}{625}\right)^{-\frac{1}{4}}+\frac{1}{\frac{64}{125}}$$

Calculate \frac{256}{625} to the power of -\frac{1}{4} and get \frac{5}{4}.

$$\frac{5}{8}+\frac{5}{4}+\frac{1}{\frac{64}{125}}$$

Add \frac{5}{8} and \frac{5}{4} to get \frac{15}{8}.

$$\frac{15}{8}+\frac{1}{\frac{64}{125}}$$

Divide 1 by \frac{64}{125} by multiplying 1 by the reciprocal of \frac{64}{125}.

$$\frac{15}{8}+1\times \frac{125}{64}$$

Multiply 1 and \frac{125}{64} to get \frac{125}{64}.

$$\frac{15}{8}+\frac{125}{64}$$

Add \frac{15}{8} and \frac{125}{64} to get \frac{245}{64}.

$$\frac{245}{64}$$

Factor

$$\frac{5 \cdot 7 ^ {2}}{2 ^ {6}} = 3\frac{53}{64} = 3.828125$$