Solve =pi/3*15(34^2+15^2+(34*15))

$$= \frac { \pi } { 3 } \times 15 ( 34 ^ { 2 } + 15 ^ { 2 } + ( 34 \times 15 ) )$$

Evaluate

$$9455\pi \approx 29703.758539691$$

Solution Steps

Calculate 34 to the power of 2 and get 1156.

$$\frac{\pi }{3}\times 15\left(1156+15^{2}+34\times 15\right)$$

Calculate 15 to the power of 2 and get 225.

$$\frac{\pi }{3}\times 15\left(1156+225+34\times 15\right)$$

Add 1156 and 225 to get 1381.

$$\frac{\pi }{3}\times 15\left(1381+34\times 15\right)$$

Multiply 34 and 15 to get 510.

$$\frac{\pi }{3}\times 15\left(1381+510\right)$$

Add 1381 and 510 to get 1891.

$$\frac{\pi }{3}\times 15\times 1891$$

Multiply 15 and 1891 to get 28365.

$$\frac{\pi }{3}\times 28365$$

Cancel out 3, the greatest common factor in 28365 and 3.

$$9455\pi$$

Expand

$$9455\pi$$

Solution Steps

Calculate 34 to the power of 2 and get 1156.

$$\frac{\pi }{3}\times 15\left(1156+15^{2}+34\times 15\right)$$

Calculate 15 to the power of 2 and get 225.

$$\frac{\pi }{3}\times 15\left(1156+225+34\times 15\right)$$

Add 1156 and 225 to get 1381.

$$\frac{\pi }{3}\times 15\left(1381+34\times 15\right)$$

Multiply 34 and 15 to get 510.

$$\frac{\pi }{3}\times 15\left(1381+510\right)$$

Add 1381 and 510 to get 1891.

$$\frac{\pi }{3}\times 15\times 1891$$

Multiply 15 and 1891 to get 28365.

$$\frac{\pi }{3}\times 28365$$

Cancel out 3, the greatest common factor in 28365 and 3.

$$9455\pi$$