Solve =2/3+4/3/1-frac{2{3}*4/3}

$$= \frac { \frac { 2 } { 3 } + \frac { 4 } { 3 } } { 1 - \frac { 2 } { 3 } \cdot \frac { 4 } { 3 } }$$

Evaluate

$$18$$

Solution Steps

Since \frac{2}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{2+4}{3}}{1-\frac{2}{3}\times \frac{4}{3}}$$

Add 2 and 4 to get 6.

$$\frac{\frac{6}{3}}{1-\frac{2}{3}\times \frac{4}{3}}$$

Divide 6 by 3 to get 2.

$$\frac{2}{1-\frac{2}{3}\times \frac{4}{3}}$$

Multiply \frac{2}{3} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2}{1-\frac{2\times 4}{3\times 3}}$$

Do the multiplications in the fraction \frac{2\times 4}{3\times 3}.

$$\frac{2}{1-\frac{8}{9}}$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{2}{\frac{9}{9}-\frac{8}{9}}$$

Since \frac{9}{9} and \frac{8}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2}{\frac{9-8}{9}}$$

Subtract 8 from 9 to get 1.

$$\frac{2}{\frac{1}{9}}$$

Divide 2 by \frac{1}{9} by multiplying 2 by the reciprocal of \frac{1}{9}.

$$2\times 9$$

Multiply 2 and 9 to get 18.

$$18$$

Factor

$$2\times 3^{2}$$