Solve =[15/7-8/49div35]*28/3

$$= [ \frac { 15 } { 7 } - \frac { 8 } { 49 } \div 35 ] \times \frac { 28 } { 3 }$$

Evaluate

$$\frac{14668}{735}\approx 19.956462585$$

Solution Steps

Express \frac{\frac{8}{49}}{35} as a single fraction.

$$\left(\frac{15}{7}-\frac{8}{49\times 35}\right)\times \frac{28}{3}$$

Multiply 49 and 35 to get 1715.

$$\left(\frac{15}{7}-\frac{8}{1715}\right)\times \frac{28}{3}$$

Least common multiple of 7 and 1715 is 1715. Convert \frac{15}{7} and \frac{8}{1715} to fractions with denominator 1715.

$$\left(\frac{3675}{1715}-\frac{8}{1715}\right)\times \frac{28}{3}$$

Since \frac{3675}{1715} and \frac{8}{1715} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3675-8}{1715}\times \frac{28}{3}$$

Subtract 8 from 3675 to get 3667.

$$\frac{3667}{1715}\times \frac{28}{3}$$

Multiply \frac{3667}{1715} times \frac{28}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3667\times 28}{1715\times 3}$$

Do the multiplications in the fraction \frac{3667\times 28}{1715\times 3}.

$$\frac{102676}{5145}$$

Reduce the fraction \frac{102676}{5145} to lowest terms by extracting and canceling out 7.

$$\frac{14668}{735}$$

Factor

$$\frac{2 ^ {2} \cdot 19 \cdot 193}{3 \cdot 5 \cdot 7 ^ {2}} = 19\frac{703}{735} = 19.956462585034014$$