Solve +y^2-4x-2y-20=0

$$+ y ^ { 2 } - 4 x - 2 y - 20 = 0$$

Solve for x

$$x=\frac{y^{2}-2y-20}{4}$$

Steps for Solving Linear Equation

Subtract y^{2} from both sides. Anything subtracted from zero gives its negation.

$$-4x-2y-20=-y^{2}$$

Add 2y to both sides.

$$-4x-20=-y^{2}+2y$$

Add 20 to both sides.

$$-4x=-y^{2}+2y+20$$

The equation is in standard form.

$$-4x=20+2y-y^{2}$$

Divide both sides by -4.

$$\frac{-4x}{-4}=\frac{20+2y-y^{2}}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$x=\frac{20+2y-y^{2}}{-4}$$

Divide -y^{2}+2y+20 by -4.

$$x=\frac{y^{2}}{4}-\frac{y}{2}-5$$

Solve for y (complex solution)

$$y=\sqrt{4x+21}+1$$

$$y=-\sqrt{4x+21}+1$$

Solve for y

$$y=\sqrt{4x+21}+1$$

$$y=-\sqrt{4x+21}+1\text{, }x\geq -\frac{21}{4}$$