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Solve for y, x
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2x-3\times 5-4=0
Consider the second equation. Insert the known values of variables into the equation.
2x-15-4=0
Multiply -3 and 5 to get -15.
2x-19=0
Subtract 4 from -15 to get -19.
2x=19
Add 19 to both sides. Anything plus zero gives itself.
x=\frac{19}{2}
Divide both sides by 2.
y=5 x=\frac{19}{2}
The system is now solved.