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Solve for x, y (complex solution)
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Solve for x, y
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by=c,\left(-a\right)y+bx=c
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
by=c
Pick one of the two equations which is more simple to solve for y by isolating y on the left hand side of the equal sign.
y=\frac{c}{b}
Divide both sides by b.
\left(-a\right)\times \frac{c}{b}+bx=c
Substitute \frac{c}{b} for y in the other equation, \left(-a\right)y+bx=c.
-\frac{ac}{b}+bx=c
Multiply -a times \frac{c}{b}.
bx=\frac{c\left(a+b\right)}{b}
Add \frac{ac}{b} to both sides of the equation.
x=\frac{c\left(a+b\right)}{b^{2}}
Divide both sides by b.
y=\frac{c}{b},x=\frac{c\left(a+b\right)}{b^{2}}
The system is now solved.
by=c,\left(-a\right)y+bx=c
To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.
by=c
Pick one of the two equations which is more simple to solve for y by isolating y on the left hand side of the equal sign.
y=\frac{c}{b}
Divide both sides by b.
\left(-a\right)\times \frac{c}{b}+bx=c
Substitute \frac{c}{b} for y in the other equation, \left(-a\right)y+bx=c.
-\frac{ac}{b}+bx=c
Multiply -a times \frac{c}{b}.
bx=\frac{c\left(a+b\right)}{b}
Add \frac{ac}{b} to both sides of the equation.
x=\frac{c\left(a+b\right)}{b^{2}}
Divide both sides by b.
y=\frac{c}{b},x=\frac{c\left(a+b\right)}{b^{2}}
The system is now solved.