Solve for x
x\leq \frac{2}{3}
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3x+11\leq 13
Swap sides so that all variable terms are on the left hand side. This changes the sign direction.
3x\leq 13-11
Subtract 11 from both sides.
3x\leq 2
Subtract 11 from 13 to get 2.
x\leq \frac{2}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
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