Solve +m^2-8/2m=0

$$+ \frac { m ^ { 2 } - 8 } { 2 m } = 0$$

Solve for m

$$m=2\sqrt{2}\approx 2.828427125$$

$$m=-2\sqrt{2}\approx -2.828427125$$

Steps by Finding Square Root

Variable m cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2m.

$$m^{2}-8=0$$

Add 8 to both sides. Anything plus zero gives itself.

$$m^{2}=8$$

Take the square root of both sides of the equation.

$$m=2\sqrt{2} m=-2\sqrt{2}$$

Steps Using the Quadratic Formula

Variable m cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2m.

$$m^{2}-8=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\left(-8\right)}}{2}$$

Square 0.

$$m=\frac{0±\sqrt{-4\left(-8\right)}}{2}$$

Multiply -4 times -8.

$$m=\frac{0±\sqrt{32}}{2}$$

Take the square root of 32.

$$m=\frac{0±4\sqrt{2}}{2}$$

Now solve the equation m=\frac{0±4\sqrt{2}}{2} when ± is plus.

$$m=2\sqrt{2}$$

Now solve the equation m=\frac{0±4\sqrt{2}}{2} when ± is minus.

$$m=-2\sqrt{2}$$

The equation is now solved.

$$m=2\sqrt{2} m=-2\sqrt{2}$$