Solve +4/3b-2/3>0

$$+ \frac { 4 } { 3 } b - \frac { 2 } { 3 } > 0$$

Solve for b

$$b>\frac{1}{2}$$

Solution Steps

Add \frac{2}{3} to both sides. Anything plus zero gives itself.

$$\frac{4}{3}b>\frac{2}{3}$$

Multiply both sides by \frac{3}{4}, the reciprocal of \frac{4}{3}. Since \frac{4}{3} is positive, the inequality direction remains the same.

$$b>\frac{2}{3}\times \frac{3}{4}$$

Multiply \frac{2}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$b>\frac{2\times 3}{3\times 4}$$

Cancel out 3 in both numerator and denominator.

$$b>\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$b>\frac{1}{2}$$