Solve for x
x = \frac{27}{4} = 6\frac{3}{4} = 6.75
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6-\frac{2}{3}x=\frac{3}{2}
Swap sides so that all variable terms are on the left hand side.
-\frac{2}{3}x=\frac{3}{2}-6
Subtract 6 from both sides.
-\frac{2}{3}x=\frac{3}{2}-\frac{12}{2}
Convert 6 to fraction \frac{12}{2}.
-\frac{2}{3}x=\frac{3-12}{2}
Since \frac{3}{2} and \frac{12}{2} have the same denominator, subtract them by subtracting their numerators.
-\frac{2}{3}x=-\frac{9}{2}
Subtract 12 from 3 to get -9.
x=-\frac{9}{2}\left(-\frac{3}{2}\right)
Multiply both sides by -\frac{3}{2}, the reciprocal of -\frac{2}{3}.
x=\frac{-9\left(-3\right)}{2\times 2}
Multiply -\frac{9}{2} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
x=\frac{27}{4}
Do the multiplications in the fraction \frac{-9\left(-3\right)}{2\times 2}.
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