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2 + x = 18

Rozwiąż względem x

x = 16

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Linear Equation

2 + x = 18

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Let P(x) be a polynomial of degree 4 , having extremum at

x = 1, x = 2

lim_{x \to 0} \frac{x ^{2} + P ( x )}{x ^{2}} = 2

Then the value of P(2)

https://math.stackexchange.com/q/762464

P (x) = a + b x + c x^{2} + d x^{3} + e x^{4}

. Given the limit statement, we have

lim_{x \to 0} e x^{2} + d x + (c + 1) + \frac{b}{x} + \frac{a}{x ^{2}} = 2

The only way that this is possible is to have

a = b = 0

Udostępnij

Skopiowano do schowka

x=18-2

Odejmij 2 od obu stron.

x=16

Odejmij 2 od 18, aby uzyskać 16.

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