Rozwiąż (2n-1/n^2)^25

$$( 2 n - \frac { 1 } { n ^ { 2 } } ) ^ { 25 }$$

Oblicz

$$\frac{\left(2n^{3}-1\right)^{25}}{n^{50}}$$

Rozwiń

$$33554432n^{25}-419430400n^{22}[phone]n^{19}-9646899200n^{16}[phone]n^{13}-55710842880n^{10}[phone]n^{7}-126012620800n^{4}[phone]n-\frac{133888409600}{n^{2}}+\frac{107110727680}{n^{5}}-\frac{73030041600}{n^{8}}+\frac{42600857600}{n^{11}}-\frac{21300428800}{n^{14}}+\frac{9128755200}{n^{17}}-\frac{3347210240}{n^{20}}+\frac{1046003200}{n^{23}}-\frac{276883200}{n^{26}}+\frac{61529600}{n^{29}}-\frac{11334400}{n^{32}}+\frac{1700160}{n^{35}}-\frac{202400}{n^{38}}+\frac{18400}{n^{41}}-\frac{1200}{n^{44}}+\frac{50}{n^{47}}-\frac{1}{n^{50}}$$