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Solvi għal x
x=\pi n_{1}+\frac{\pi }{4}
n_{1}\in \mathrm{Z}
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Trigonometry
\sin ( x ) = \cos ( x )
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https://math.stackexchange.com/questions/1476944/how-to-solve-equations-like-2-sinx-cosx/1476973
One way can be using tan\frac x2=t so sin x=\frac{2t}{1+t^2} and cos x=\frac{1-t^2}{1+t^2}. Here 2sin x= cos x implies t^2+4t-1=0 from wich tan \frac x2=2\pm\sqrt{5}.Hence the answer of ...
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Bdub Nov 12, 2016 Pick a value for x like \displaystyle\frac{\pi}{{3}} and plug it in to both side to show that they don't equal each other and therefore not an identity
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https://socratic.org/questions/how-do-you-solve-1-sin-x-cos-x
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https://math.stackexchange.com/q/2212333
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