4=sqrt{ax}+a/sqrt{ax} を解きます| Microsoft 数学ソルバー

$$4 = \sqrt { a x } + \frac { a } { \sqrt { a x } }$$

a を解く (複素数の解)

$$a=\frac{16x}{\left(x+1\right)^{2}}$$

$$x\neq 0\text{ and }x\neq -1\text{ and }arg(\frac{4x^{2}+4x}{\left(x+1\right)^{2}})<\pi$$

x を解く (複素数の解)

$$\left\{\begin{matrix}x=\frac{\left(\sqrt{4-a}+2\right)^{2}}{a}\text{, }&a\neq 0\text{ and }arg(\sqrt{4-a}+2)<\pi \\x=-\frac{a+4\sqrt{4-a}-8}{a}\text{, }&arg(-\sqrt{4-a}+2)<\pi \text{ and }a\neq 0\end{matrix}\right.$$

a を解く

$$a=\frac{16x}{\left(x+1\right)^{2}}$$

$$x>0\text{ or }x<-1$$

x を解く

$$\left\{\begin{matrix}x=\frac{\left(\sqrt{4-a}+2\right)^{2}}{a}\text{, }&a\neq 0\text{ and }a\leq 4\\x=-\frac{a+4\sqrt{4-a}-8}{a}\text{, }&a\leq 4\text{ and }-\sqrt{4-a}+2\geq 0\text{ and }a\neq 0\end{matrix}\right.$$