4sinθcosθ=2sinθ を解きます| Microsoft 数学ソルバー

θ を解く

θ = 2 π n_{2} + \frac{π}{3}, n_{2} \in Z

θ = 2 π n_{3} + \frac{5 π}{3}, n_{3} \in Z

θ = π n_{1}, n_{1} \in Z

Tick mark Image

グラフ

クイズ

4 sin θ cos θ = 2 sin θ

Web 検索からの類似の問題

Why do we lose solutions when we divide

2 sin θ cos θ = sin θ

sin θ

https://math.stackexchange.com/q/2806858

Whenever you divide both sides of an equation by something, you are assuming that the thing you're dividing by is nonzero, because dividing by

0

is not valid. So going from

2 sin θ cos θ = sin θ

Simple Trig Equations - Why is it Wrong to Cancel Trig Terms?

https://math.stackexchange.com/questions/1416619/simple-trig-equations-why-is-it-wrong-to-cancel-trig-terms

The two issues are: When cancelling a factor, note that this is only possible when the factor is not zero; but the factor may be zero in the solution to the problem. In this case

sin θ = 0

How do I simplify this expression further?

https://math.stackexchange.com/questions/472115/how-do-i-simplify-this-expression-further

\frac{1}{x ^{2} + y ^{2}} = 1 + ∣ ∣ ∣ ∣ \frac{2}{y ^{2} / x ^{2} + 1} - 1 ∣ ∣ ∣ ∣ = 1 + \frac{∣ x ^{2} - y ^{2} ∣}{x ^{2} + y ^{2}},

or put differently

1 = x^{2} + y^{2} + ∣ x^{2} - y^{2} ∣ .

At this point solving by cases helps. Where

∣ x ∣ < ∣ y ∣

Using the exponential form of a complex number and De Moivre's theorem

https://math.stackexchange.com/questions/1523448/using-the-exponential-form-of-a-complex-number-and-de-moivres-theorem

cos (2 θ + π / 2) = R e (e^{i (2 θ + π / 2)})

e^{i (2 θ + π / 2)} = (e^{i θ})^{2} e^{i π / 2} = (cos θ + i sin θ)^{2} (i)

= i (cos^{2} θ + 2 i cos θ sin θ - sin^{2} θ)

Is the point of a shape with the greatest average ray length also the “centroid”?

https://math.stackexchange.com/questions/1588150/is-the-point-of-a-shape-with-the-greatest-average-ray-length-also-the-centroid

I have confused you with the definition of mean radius with the average ray length. When people think of average radius they think of "average squared minimized" or mean radius. What I am focusing on ...

Do we have to show it for both cases?

https://math.stackexchange.com/questions/1459841/do-we-have-to-show-it-for-both-cases

C = c + π

sin (θ + C) = - sin (θ + c)

, so having the

\pm

there doesn't create any more solutions if you allow any

c \in [0, 2 π)

共有

reddit

コピー

クリップボードにコピー済み

例

二次方程式の公式

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

一次方程式

y = 3 x + 4

699 * 533

マトリックス

[2534] [2 - 1 0135]

連立方程式

{8 x + 2 y = 46 7 x + 3 y = 47

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}